consider a silver wire with a radius of 4.0 x 10^-3 meter. determine the cross sectional area of this wire

5.024*10⁻⁵ m

Explanation:

A = πr² ... Equation 1

Where A = cross sectional area of the wire, r = radius of the wire, π = pie.

Given: r = 4.0*10⁻³ meter.

Constant: π = 3.14.

Substitute these values into equation 1

A = 3.14 (4.0*10⁻³) ²

A = 3.14*16*10⁻⁶

A = 50.24*10⁻⁶

A = 5.024*10⁻⁵ m.

Hence the cross sectional area of the wire = 5.024*10⁻⁵ m