A truck with a mass of 1.5 x 103 kg accelerates to a speed of 18.0 m/s in 12.0 s from a dead stop. Assume that the force of resistance is a constant 400.0 N during the acceleration. What is the average power developed by the truckÍs engine?

There are several information's already given in the question. Based on those information's the answer can be easily deduced.

Mass of the truck = 1.5 x 10^3 kg

Constant force of resistance = 400 N

Final Velocity = 18 m/s

Initial velocity = 0 m/s

Time taken = 12 s

Then

Acceleration = (Final velocity - initial velocity) / Time

= 18 / 12

= 3/2

= 1.5 m/s^2

Then

Driving force = Mass * Acceleration

= 1.5 * 10^3 * 1.5

= 2250 N

So

Net Force = 2250 - 400

= 1850 N

Average power developed = 1850 * 18

= 3.33 * 10^4 W

Power = Net Force x velocity

Net force = driving force - force of resistance

Driving force = mass x acceleration

Acceleration = (final velocity - initial velocity) / time

Acceleration = (18 - 0) / 12 = 1.5 m/s²

Driving force = 1.5 x 10³ x 1.5

= 2250 N

Net force = 2250 - 400

= 1850

Power = 1850 x 18

= 3.33 x 10⁴ Watts