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17 March, 15:17

A 15.0-kg block of ice at 0.00 °c falls into lake superior, which is a freshwater lake. the lake water is at 10.0 °c, and the latent heat of fusion for ice is 3.34 * 105 j/kg. find the various changes in entropy due to the melting of the ice.

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  1. 17 March, 15:36
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    We are given:

    mass of ice = 15 kg

    Ti = 0 degrees Celsius

    Tf = 10 degrees Celsius

    Latent heat of fusion for ice = 3 ... 34x10^5 J/kg

    The formula for entropy:

    S = mH / (Tf - Ti)

    S = 15 kg * 3.34x10^5 J/kg / (10-0)

    S = 501 kg/K
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