For an isothermal process, the work done by or on a system of ideal gas is equal to the change in what?

For an ideal gas, the work done is the area under the P-V (pressure-volume) curve.

When the process is isothermal, the temperature does not change, and the work done is proportional to ln (V₂/V₁),

where V₁ and V₂ are initial and final volumes.

Furthermore, the internal. energy remains constant.

Answer:

(a) There will be change in volume,

(b) There will be no change in temperature,

(c) There will be no change in internal energy.