A block of mass 2m is moving in the positive x-direction with velocity + 4v. Another block of mass 3m is moving in the negative x-direction with velocity - v a. [5 pt] Find the velocity of the center of mass of the two block

Answer: the velocity of the center of mass of the two block is v.

Explanation:

Hi, to answer this question we have to apply the next formula:

vcm = [ m1v1 + m2v2] / (m1+m2)

Where:

vcm = velocity of the center of mass

m1 = mass 1, m2 = mass2

v1 = velocity 1; v2 = velocity 2

Replacing with the values given:

vcm = (2 (4v) - 3v) / (2+3) = (8v-3v) / 5 = 5v/5 = v

The velocity of the center of mass of the two block is v.

Feel free to ask for more if needed or if you did not understand something.