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6 March, 03:25

A coil with a self-inductance of 3.0 H and a resistance of 100Ω carries a steady current of 2.0 A. (a) What is the energy stored in the magnetic field of the coil? (b) What is the energy per second dissipated in the resistance of the coil?

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  1. 6 March, 03:47
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    energy stored in the magnetic field of coil is 6 J

    energy per second dissipated in the resistance of the coil is 400 W

    Explanation:

    Given data

    inductance = 3.0 H

    resistance = 100Ω

    current = 2.0 A

    to find out

    energy stored in the magnetic field and energy per second dissipated

    solution

    we know that energy stored in the magnetic field is express as

    E = 1/2 * L*I²

    here E is energy store and L is inductance and I is current

    put all value we get

    E = 1/2 * L*I²

    E = 1/2 * 3 * 2²

    E = 6 J

    energy stored in the magnetic field of coil is 6 J

    and

    energy per second is power

    so power = I²*R

    power = 2² * 100

    power = 400 W

    so energy per second dissipated in the resistance of the coil is 400 W
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