Nana manages to stop their decent. While stopped, with the axe in the ice, her coefficient of static friction is LaTeX: / mu_s=2.8μ s = 2.8. What is the maximum acceleration ice Popo can climb up the rope, without causing them to slide again?

Question

Annika Hull

Physics

22 November, 08:57

Nana manages to stop their decent. While stopped, with the axe in the ice, her coefficient of static friction is LaTeX: / mu_s=2.8μ s = 2.8. What is the maximum acceleration ice Popo can climb up the rope, without causing them to slide again?

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Answers (1)

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Arjun Collins · Answer 1

Acceleration, a = 1.65m/s^2

Acceleration is downward.

Explanation:

y: N - m1gcosalpha=0

x: Ff - FT - m1gsinalpha = m1 * alpha

Ff = uN = um1gcosalpha

FT=m2g

Acceleration, a = g (ucosalpha - (m2/m1) - sin alpha)

a = (m2/m1) + sinalpha = 1.976

Cos alpha = 0.766

U2 = 2.8

a = g (2.8*0.766) - 1.976)

a = g * 0.1688

a = 9.8 * 0.1688

a=1.65m/s^2