2. A 100 kg box initially traveling at 10 m/s encounters a frictional force and takes 5 seconds to

slow down to a stop.

a. Determine the acceleration of the box (direction matters + or - )

b. If friction is the only unbalanced force, what is its value?

Question

Valery

Physics

20 April, 19:10

2. A 100 kg box initially traveling at 10 m/s encounters a frictional force and takes 5 seconds to

slow down to a stop.

a. Determine the acceleration of the box (direction matters + or - )

b. If friction is the only unbalanced force, what is its value?

+3

Answers (1)

Know the Answer?

Nehemiah Saunders · Answer 1

a. - 2 m/s²

b. - 200 N

Explanation:

2a.

Given:

v₀ = 10 m/s

v = 0 m/s

t = 5 s

Find: a

v = at + v₀

(0 m/s) = a (5 s) + (10 m/s)

a = - 2 m/s²

2b.

Newton's second law:

∑F = ma

F = (100 kg) (-2 m/s²)

F = - 200 N

2. A 100 kg box initially traveling at 10 m/s encounters a frictional force and takes 5 seconds toslow down to a stop.a. Determine the acceleration of the box (direction matters + or - )b. If friction is the only unbalanced force, what is its value?

2. A 100 kg box initially traveling at 10 m/s encounters a frictional force and takes 5 seconds to

slow down to a stop.

a. Determine the acceleration of the box (direction matters + or - )

b. If friction is the only unbalanced force, what is its value?