On a day when the barometer reads 75.23 cm, a reaction vessel holds 250 mL of ideal gas at 20 celsius. An oil manometer (rho = 810 kg/m^3) reads the pressure in the vessel to be 41 cm of oil and below atmospheric pressure. What volume will the gas occupy under S. T. P.?

Question

Nolan Munoz

Physics

22 May, 12:28

On a day when the barometer reads 75.23 cm, a reaction vessel holds 250 mL of ideal gas at 20 celsius. An oil manometer (rho = 810 kg/m^3) reads the pressure in the vessel to be 41 cm of oil and below atmospheric pressure. What volume will the gas occupy under S. T. P.?

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Answers (1)

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Briley · Answer 1

V2 = 8.25 ml

Explanation:

First we will list down the data that is given to us:

V1 = 250 ml

T1 = 20° C + 273K = 293K

T2 = 25° C + 273K = 298K (AT STP)

Density at STP = 13600 kg/m^3

First we will calculate the pressure inside the vessel using the formula

P = (ρ) (g) (h)

P1 = (810) (9.8) (0.41)

P1 = 3254.58 pa

P2 = (13600) (9.8) (0.7523)

P2 = 100266.544 pa

Now in order calculate the volume that the gas occupies we will use the following formula,

(P1*V1) / T1 = (P2*V2) / T2

Making V2 as the subject of the equation we get,

V2 = (P1*V1*T2) / (P2*T1)

V2 = (3254.58*250*298) / (100266.544*293)

V2 = 8.25 ml