A coin is placed on a vinyl stereo record that is making 33 1/3 revolutions per minute on a turntable. (a) In what direction is the acceleration of the coin? (b) Find the magnitude of the acceleration when the coin is placed 5.0, 10, and 14 cm from the center of the record.

Question

Cecelia Guzman

Physics

6 August, 05:29

A coin is placed on a vinyl stereo record that is making 33 1/3 revolutions per minute on a turntable. (a) In what direction is the acceleration of the coin? (b) Find the magnitude of the acceleration when the coin is placed 5.0, 10, and 14 cm from the center of the record.

+4

Answers (1)

Know the Answer?

Mira Clayton · Answer 1

Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac = 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2

Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:

ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.

w=2*π*f

We know that the turntable is set to 33 1/3 rev/m so

the frequency 33.33/60=0.55 Hz

then w=2*π*0.55=3.45 rad/s

Finally the centripetal acceleration at differents radii results equal:

r = 0.05 m ac=3.45^2*0.05=0.50 m/s^2

r=0.1 ac=3.45^2*0.1=1.20 m/s^2

r=0.14 ac=3.45^2*0.14=1.66 m/s^2