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18 August, 01:48

A rigid tank internal energy of fluid 800kJ. Fluid loses 500kJ of heat and padle wheel does 100kJ of work. Find final internal energy in tank.

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  1. 18 August, 02:17
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    U₂ = 400 KJ

    Explanation:

    Given that

    Initial energy of the tank, U₁ = 800 KJ

    Heat loses by fluid, Q = - 500 KJ

    Work done on the fluid, W = - 100 KJ

    Sign -

    1. Heat rejected by system - negative

    2. Heat gain by system - Positive

    3. Work done by system = Positive

    4. Work done on the system-Negative

    Lets take final internal energy = U₂

    We know that

    Q = U₂ - U₁ + W

    -500 = U₂ - 800 - 100

    U₂ = - 500 + 900 KJ

    U₂ = 400 KJ

    Therefore the final internal energy = 400 KJ
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