An arrow is shot vertically upward from a platform 33ft high at a rate of 214ft/sec. when will the arrow hit the ground? use the formula: h=-16t2+v0t+h0. (round your answer to the nearest tenth.)

Time = 11.1 seconds

Explanation:

h = - 16t^2 + v (0) t + h (0)

but we are given;

v (0) = 174 ft/sec

h (0) = 33 ft

Find h = 0:

Therefore;

0 = - 16t^2 + 174t + 33

16t^2 - 174t - 33 = 0

Use the quadratic equation:

a = 16

b = - 174

c = - 33

t = (174 + / - sqrt ((-174) ^2 - 4 (16) (-33))) / 2 (16)

t = (174 + / - sqrt (30276 + 2112)) / 32

t = (174 + / - sqrt (32388)) / 32

t = (174 + / - 179.97) / 32

t = 353.97/32 or - 5.97/32

t = 11.1 or -.2

Therefore;

The arrow will hit the ground at:

t = 11.1 sec