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20 March, 19:56

Early one February morning you go outside to build a snow man. You make a 3.2kg snowball and lift it to a height of 1.2m, then carry it 25m on level ground with a force of 1.0N to your snowman and then lift it up the rest of the way to set as the head of a 2.3m snowman. How much work do you do on the snowball as you transport it and position it on your masterpiece?

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  1. 20 March, 20:02
    0
    Here you go

    First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

    Therefore mass * gravitational pull*height will give us the work done

    =3.2kg * 9.8N/kg*1.2m

    =37.632J

    then, the work done over the 25m distance if found by the following formula: work done=force*distance

    =1.0N*25m

    =25J

    On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.

    therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m

    =m*g*h

    =3.2kg*9.8N/kg*1.1m

    =34.496J

    To get the total we add the amount of work done in the various instances.
  2. 20 March, 20:18
    0
    First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

    Therefore mass * gravitational pull*height will give us the work done

    =3.2kg * 9.8N/kg*1.2m

    =37.632J

    then, the work done over the 25m distance if found by the following formula: work done=force*distance

    =1.0N*25m

    =25J

    On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.

    therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m

    =m*g*h

    =3.2kg*9.8N/kg*1.1m

    =34.496J

    To get the total we add the amount of work done in the various instances.
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