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26 January, 13:26

The secondary coil of a neon sign transformer provides 7500 V at 0.01 A. The primary coil operates on 120 V. What is the input current in the primary coil of this transformer assuming that no energy is lost in the transformer?

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  1. 26 January, 13:38
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    0.625 A

    Explanation:

    Vs = 7500 V, Is = 0.01 A

    Vp = 120 V

    Let the primary current be Ip.

    As the transformer is ideal, so input power is equal to the output power

    Vp x Ip = Vs x Is

    120 x Ip = 7500 x 0.01

    Ip = 0.625 A
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