A 4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment, is accelerating at 1.1 m/s2 on level ground with friction having no significant effect. what is the normal force on the sled?

Question

Ruby Weiss

Physics

31 January, 12:44

A 4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment, is accelerating at 1.1 m/s2 on level ground with friction having no significant effect. what is the normal force on the sled?

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Answers (2)

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Conner Oconnell · Answer 1

Normal force is equal to the formula of mg where m is the gravitational acceleration and g is the mass of the object. This is only applicable when the force is acting in the direction of the gravitational field and the object is placed horizontally. So the formula is normal force = mg since the problem depicts what the statement is talking about.

So NF = mg = 9.8 m/s^2 * 4.2kg = 41.16 N or 41 N

Alexis Ayers · Answer 2

the body is moving horizontally, it doesnt matter watever kind of horizontal forces are acting.

Therefore the normal force is equal to the weight

N=mg=4.2*9.8=41N

Note: the other data in the problem have no relevance

answer

the normal force on the sled is 41N