Suppose a car battery has an internal resistance of 0.02 ohms. The voltage between terminals when no current is flowing is 13.6 volts. (The usual value of "12 volts" for lead-acid batteries is only nominal; the actual voltage is higher.) When the battery is supplying 80 A of current to a starter motor, what is the voltage between the terminals of the battery? 1 1.6

Question

Deandre Mccoy

Physics

24 December, 07:47

Suppose a car battery has an internal resistance of 0.02 ohms. The voltage between terminals when no current is flowing is 13.6 volts. (The usual value of "12 volts" for lead-acid batteries is only nominal; the actual voltage is higher.) When the battery is supplying 80 A of current to a starter motor, what is the voltage between the terminals of the battery? 1 1.6

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Ayaan Castro · Answer 1

When the battery is supplying 80A of current, the voltage drop across its internal resistance is

V = (current) · (resistance)

V = (80A) · (0.02 Ω)

V = 1.6 volts

The voltage that appears across the terminals of the battery is

V = (13.6 - 1.6)

V = 12.0 volts