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21 October, 05:46

A small boat is moving at a velocity of 3.35 when it is accelerated by a river current perpendicular to the initial direction of motion. If the acceleration of the current is 0.750 m/s2, what will be the new velocity of the boat after 3.35s?

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Answers (2)
  1. 21 October, 05:58
    0
    Given Information:

    Acceleration = a = 0.750 m/s²

    Initial velocity = v₁ = 3.35 m/s

    time = t = 3.35 seconds

    Required Information:

    new velocity = v₂ = ?

    Answer:

    new velocity = 5.86 m/s

    Explanation:

    We know from the kinematic equations,

    v = u + at

    Here u = v₁ and v = v₂

    v₂ = v₁ + at

    v₂ = 3.35 + 0.750*3.35

    v₂ = 3.35 + 2.512

    v₂ = 5.86 m/s

    Therefore, the new velocity of the boat after it was accelerated by a river current is 5.86 m/s.
  2. 21 October, 06:12
    0
    The answer is 5.86m/s

    Explanation:

    Acceleration is defined as the change in velocity of a body with respect to time. Mathematically,

    Acceleration = change in velocity/time (t)

    Change in velocity = final velocity (v) - initial velocity (u)

    Acceleration = v-u/t

    Given the following;

    Acceleration = 0.75m/s²

    Initial velocity = 3.35m/s

    Time taken = 3.35s

    Final velocity = v

    Substituting the data given in the formula to get the final velocity we have;

    0.75 = (v-3.35) / 3.35

    0.75*3.35 = v-3.35

    2.51 = v-3.35

    v = 2.51+3.35

    v = 5.86m/s

    Therefore the new velocity of the object will be 5.86m/s
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