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10 September, 10:34

An 8000-N car is traveling at 12 m/s along a horizontal road. When the brakes are applied, the car skids (slides) to a stop in 4.0 s. Find the work done on the car.

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  1. 10 September, 10:46
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    192000 J or 192 kJ

    Explanation:

    Work done = Force * distance moved along the direction of force.

    From the question,

    W = F*d ... Equation 1

    Where W = work done by the car, F = Force of the car, d = distance move by the car along the direction of the force.

    We can calculate for d using the equation of motion

    d = (v+u) t/2 ... Equation 2

    Where v = Final velocity of the car, u = Initial velocity of the car, t = time.

    Given: u = 12 m/s, v = 0 m/s (skids to a stop), t = 4.0 s

    Substitute into equation 2

    d = (12+0) 4/2

    d = 24 m.

    Also given: F = 8000 N

    Substitute into equation 1

    W = 8000*24

    W = 192000 J

    W = 192 kJ.
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