If you push an object twice as far while applying the same force, you do ...

The work done is doubled

Explanation:

The work done on an object by a force is (assuming the force is parallel to the displacement of the object)

W = Fd

where

W is the work done

F is the magnitude of the force

d is the displacement of the object

In this problem:

- the force applied is the same

- the displacement of the object is doubled, d' = 2d

So the new work done will be

W' = Fd' = F (2d) = 2 (Fd) = 2 W

So, the work done is doubled.