During a softball game, a batter hits a ball upward from an initial height of 3 feet. the height, in feet, of the softball is given by s (t) = - 16t+70t+3, where t is the time in seconds and t>=0 which is the closest to the time when the softball will be 50 feet above the ground?

Question

Nyasia Farmer

Physics

7 February, 10:36

During a softball game, a batter hits a ball upward from an initial height of 3 feet. the height, in feet, of the softball is given by s (t) = - 16t+70t+3, where t is the time in seconds and t>=0 which is the closest to the time when the softball will be 50 feet above the ground?

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Answers (1)

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Marques Woodard · Answer 1

The problem provides us with a formula which relates the distance as a function of time. Since the problem wants to find the time given the distance of 50 feet, then this formula is useful. Just substitute s = 50 and solve for t.

50 = - 16t + 70t + 3

Solving for t,

t = 0.87 s