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10 July, 01:27

determine the pressure exerted on the surface of a submarine cruising 175 ft below the free surface of the sea. assume that the barometric pressure is 14.7 psia and the specific gravity of seawater is 1.03.

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  1. 10 July, 01:30
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    92.81 psia.

    Explanation:

    The density of water by multiplying its specific gravity by the density of sea water.

    SG = density of sea water/density of water

    ρ = SG x ρw

    1 kg/m3 = 62.4 lbm/ft^3

    = 1.03 * 62.4

    = 64.27lbm/ft^3.

    The absolute pressure at 175 ft below sea level as this is the location of the submarine.

    P = Patm + ρgh

    = 14.7 + 64.27 * 32.2 * 175

    Converting to pound force square inch,

    = 14.7 + 64.27 * (32.2ft/s^2) * (175ft) * (1lbf/32.2lbm⋅ft/s^2) * (1ft^2/144in^2)

    = 14.7 + 78.11 psia

    = 92.81 psia.
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