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19 August, 14:54

The distance of the earth from the sun is 93 000 000 miles. if there are 3.15 * 107 s in one year, find the speed of the earth in its orbit about the sun.

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  1. 19 August, 15:19
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    The angular velocity of the orbit about the sun is:

    w = 1 rev / year = 1 rev / 3.15 * 10^7 s

    Now in 1 rev there is 360° or 2π rad, therefore:

    w = 2π rad / 3.15 * 10^7 s

    To convert in linear velocity, multiply the rad / s by the radius:

    v = (2π rad / 3.15 * 10^7 s) * 93,000,000 miles

    v = 18.55 miles / s = 29.85 km / s
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