A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal. When sleeping, the average adult burns expends about 0.42 Cal/h for every pound of body weight.

How long would the person have to sleep continuously to lose 1 lb of body fat? (Assume the person weighs 140 lb.)

Question

Annika Hull

Physics

16 February, 03:54

A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal. When sleeping, the average adult burns expends about 0.42 Cal/h for every pound of body weight.

How long would the person have to sleep continuously to lose 1 lb of body fat? (Assume the person weighs 140 lb.)

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Answers (1)

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Grey · Answer 1

1166667hrs

Explanation:

1lb contains 3,500 Cal

There 140lb contains 3,500 * 140 = 490000cal

But he burns 0.42cal in 1 hour.

Therefore 490000cal will be burnt in 490000/0.42 = 1166667hrs to the nearest whole.

A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal. When sleeping, the average adult burns expends about 0.42 Cal/h for every pound of body weight.How long would the person have to sleep continuously to lose 1 lb of body fat? (Assume the person weighs 140 lb.)

A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal. When sleeping, the average adult burns expends about 0.42 Cal/h for every pound of body weight.

How long would the person have to sleep continuously to lose 1 lb of body fat? (Assume the person weighs 140 lb.)