A luggage handler pulls a 20.0 kg suitcase up a ramp inclined at 33.0 ∘ above the horizontal by a force F⃗ of magnitude 161 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is μk = 0.300. The suitcase travels 3.90 m along the ramp.

1. Wf = 627.9 J

2. Wg = 416.32J

3. Work done by normal force = 0 always

4. Wk = 192.3J

5. Wt = 19.28 J

Explanation:

The question have no questions specific so here some possible questions:

1) Calculate the work done on the suitcase by the force F

2) Calculate the work done on the suitcase by the gravitational force.

3) Calculate the work done on the suitcase by the normal force.

4) Calculate the work done on the suitcase by the friction force.

5) Calculate the total work done on the suitcase.

1)

work = F * d

Wf = 161N * 3.90m

Wf = 627.9 J

2)

work = mgh

Wg = 20kg*9.8m/s² * 3.9m*sin33º

Wg = 416.32J

3)

Work done by normal force = 0 always

4)

friction work = µmgdcosΘ

Wk = 0.30*20kg * 9.8m/s²*3.90m*cos33º

Wk = 192.3J

5)

total work = (627.9 - 416.32 - 192.3) J

Wt = 19.28 J