A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this time, the train moves a

distance of

meters.

Answer: 400m

Explanation:

In theory and for a train with an initial velocity the expression reads

Eq. (1) : Velocity = Initial Velocity + Acceleration*Time v = v0 + at

We also know that the distance expression for a train with a initial velocity that then accelerates reads

Eq. (2) : Distance = 0.5 * (Velocity + Initial Velocity) * Time d = 0.5 * (v0 + v) * t

Now subsituting in Eq. (1) for all known value we can obtain the Velocity after the acceleration of the train as such:

v = 20 + (4 * 10)

v = 20 + 40

v = 60m/s

Then plugging in the value for v above, in Eq. (2) we get:

d = 0.5 * (20 + 60) * 10

d = 0.5 * (80) * 10

d = 400m