A 4.0 kg food pack was dropped from a height of 200 m by a helicopter during flood relief operations. At what velocity will the food pack be falling halfway to the ground?

Given:

Distance, s = 100 m

Initial velocity, u = 0 m/s

Acceleration, a = 9.8 m/s^2

Using equations of motion,

V^2 = u^2 + 2as

V = sqrt (2 * 9.8 * 100)

= 44.47 m/s

Velocity at halfway down to the ground is 44.45 m/s and as tge food package keeps going down (dustance to the ground reduces), the velocity increases.