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16 August, 18:40

From the half-life for 14c decay, 5715 yr, calculate the age of the shroud.

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  1. 16 August, 18:50
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    Are you referring to this question?

    "The cloth shroud from around a mummy is found to have a 14C activity of 9.7 disintegrations per minute per gram of carbon as compared with living organisms that undergo 16.3 disintegrations per minute per gram of carbon. From the half-life for 14C decay, 5715 yr, calculate the age of the shroud. (Radioactive decay follows the first-order kinetics.) "

    Solution:

    [A]₀ = 16.3 dpm/g

    [A]∨t = 9.7 dpm/g

    t ∨1/2 = 5715 yr.

    t=?

    [A]₀ / [A]∨t = 16.3/9.7 = 2 ∧t/t ∨1/2

    t/t∨1/2 = log 1.168 / log 2 = 0.225 / 0.301

    = 0.747

    5715 years * 0.747 = 4270 years
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