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1 November, 06:03

The drag force F on a boat varies jointly with the wet surface area A of the boat and the square of the speed s of the boat. A boat with a wet surface area of 83 ft 2 traveling at 20 mph experiences a drag force of 996 N. Find the wet surface area of a boat traveling 18 mph and experiencing a drag force of 1215 N.

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  1. 1 November, 06:28
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    Wet surfaces areaA=+25.3ft^2

    Explanation:

    Using F = K*A * S^2

    Where F = drag force

    A = surface area

    S = speed

    Given : F=996N S=20mph A = 83ft^2

    K = F/AS^2=996 / (83*20^2)

    K = 996/33200 = 0.03

    1215 = (0.03) * A * 18^2

    1215=9.7A

    A=1215/9.7=125.3ft^2
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