Ask Question
3 October, 13:10

A particle is moving in a circle of radius R with constant speed. The time period of particle is T=1 second. In a time t=T/6, if the difference between average speed and magnitude of average velocity of particle is 2 m/sec, find the radius of circle

+3
Answers (1)
  1. 3 October, 13:13
    0
    at t=T/6, total distance covered = 2*pi*r/6 and displacement = r

    difference of them = 2*t

    so, 2*pi*r/6 - r = 2 (1/6) = 1/3

    r=1 / (pi-3) = 7.062
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A particle is moving in a circle of radius R with constant speed. The time period of particle is T=1 second. In a time t=T/6, if the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers