Dry air will break down if the electric field exceeds about 3.0*106v/m. part a what amount of charge can be placed on a capacitor if the area of each plate is 5.5 cm2? express your answer using two significant figures.

The solution for this problem is:The charge would be now equal to: (electric constant) multiplied by the (field strength) multiplied by the (area) so plugging in our values, will give us:8.85 * 10^-12 As / (V * m) * 3 * 10^6 V/m * 0.055 m^2 = 1.46 e-6 amperes would be the answer