While standing on the roof of a building, a child tosses a tennis ball with an initial speed of 13 m/s at an angle of 35° below the horizontal. The ball lands on the ground 2.6 s later. How tall, in meters, is the building?

Question

Wade Cruz

Physics

12 May, 22:58

While standing on the roof of a building, a child tosses a tennis ball with an initial speed of 13 m/s at an angle of 35° below the horizontal. The ball lands on the ground 2.6 s later. How tall, in meters, is the building?

+4

Answers (1)

Know the Answer?

Walls · Answer 1

building height is 52.52 m

Explanation:

given data

initial speed v = 13 m/s

angle = 35°

time = 2.6 s

to find out

how tall is building

solution

we consider here h is height of building

so

initial velocity at angle 35 is express as

u = v sin (θ) ... 1

u = 13 sin35 = 7.45 m/s

so

by distance formula

h = ut + 1/2 at² ... 2

h = 7.45 (2.6) + 1/2 * (9.81) * (2.6) ²

h = 52.52 m

so building height is 52.52 m