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31 January, 05:27

A 1451 kg car is traveling at 48.0 km/h.

How much kinetic energy does it possess? K. E. =

1.67 x 105 J

9.65 x 105 J

1.28 x 105 J

3.48 x 105 J

+2
Answers (2)
  1. 31 January, 05:31
    0
    KE = (1/2) · (1,451 kg) · (48 km/hr) ² · (1000 m/km) ² · (1 hr/3,600 sec) ²

    = (725.5) · (48 · 1000 · 1 / 3,600) ² (kg) · (km·m·hr / hr·km·sec) ²

    = (725.5) · (40/3) ² · (kg·m² / sec²)

    = 128,978 joules (rounded)
  2. 31 January, 05:48
    0
    Would be a. since KE = 1/2 m*v^2
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