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6 June, 03:33

During each cycle, a heat engine ejects 75 J of thermal energy for every 115 J of input thermal energy. This engine is used to lift a 345-kg load a vertical distance of 27.0 m at a steady rate of 52.5 mm/s. Part A How many cycles of the engine are needed to accomplish this task?

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  1. 6 June, 03:59
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    no of cycle required is 1885.3

    Explanation:

    given data

    thermal energy Q1 = 75 J

    thermal energy Q2 = 115 J

    load = 3454 kg

    distance = 27 m

    steady rate = 52.5 mm/s

    to find out

    How many cycles of the engine are need

    solution

    we find here first work done that is express as

    work done W = Q2 - Q1 ... 1

    put here all these value

    W = 115 - 75

    work done is 40 J

    so energy required is

    Energy required E = m*g*h ... 2

    put here value

    E = 285 * 9.8 * 27

    energy required = 75411 J

    so here no of cycle is

    no of cycle = energy required / work done

    put here value

    no of cycle required = 75411 / 40

    so no of cycle required is 1885.3
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