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20 February, 18:05

A parallel-plate capacitor is constructed of two horizontal 17.2 cm-diameter circular plates. A 1.2g plastic bead, with a charge of - 5.2nC is suspended between the two plates by the force of the electric field between them.

What is the charge on the positive (upper) plate?

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  1. 20 February, 18:33
    0
    Given:

    diameter, d = 0.172 m which means radius, r = 0.086 m

    mass of bead = 1.2 g

    = 0.0012 kg

    charge of bead = - 5.2 nC

    = - 5.2 * 10^-9 C

    E = Q / (p*A)

    where,

    E = electric field

    = F/Q

    = (0.012 * 9.8) / 5.2 * 10^-9

    = 2.26 * 10^7 N/C

    p = permittivity constant

    = 8.85 * 10^-12 C / (N*m^2)

    A = area of capacitor.

    = pi * r^2

    = 0.093 m^2

    Q = E*p*A

    = 2.26 * 10^7 * 8.85 * 10^-12 * 0.093

    = 1.86 * 10^-5 C
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