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20 July, 07:48

A pumpkin pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 233 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.

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  1. 20 July, 08:14
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    Given that,

    Pie diameter = 9 in

    Then, the circumference of the pie is

    P = πd = 9π in

    Then rim of the pie rotates 233 in,

    Then,

    1 Revolution of the pie is 9π in,

    So, for 233 in, we will have

    233 in / 9π in revolution

    8.24 revolution

    So, the revolution of the pie is 8.24

    1 revolution is 2πrad

    Then,

    8.24 revolution = 8.24 * 2π = 51.78 rad.

    And also, 1 revolution is 360°

    Then,

    8.24 revolution = 8.24 * 360 = 2966.4°

    So,

    In revolution, θ = 8.24 revolution

    In radian = θ = 57.78 rad

    In degree θ = 2966.4°
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