A basketball player makes a bounce pass by throwing the ball with a speed of 5.3 m/s and at an angle 12° below the horizontal. It leaves her hands 1.0 m above the floor. Calculate how far omher feet the ball hits the ground.

ball hit the ground from her feet is 1.83 m far away

Explanation:

given data

speed = 5.3 m/s

angle = 12°

height = 1 m

to find out

how far from her feet ball hit ground

solution

we consider here x is horizontal component and y is vertical component

so in vertical

velocity will be = v sin12

vertical speed u = 5.3 sin 12 = 1.1 m/s downward

and

in horizontal, velocity we know v = 5.3 m/s

so from motion of equation

s = ut + 0.5*a*t²

s is distance t is time a is 9.8

put all value

1 = 1.1 (t) + 0.5*9.8*t²

solve it we get t

t = 0.353 s

and

horizontal distance is = vcos12 * t

so horizontal distance = 5.3*cos12 * (0.353)

horizontal distance = 1.83 m

so ball hit the ground from her feet is 1.83 m far away