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5 January, 19:10

A man pushes a lawn mower on a level lawn with a force of 186.5 N. If 3.8% of this

force is directed downward, then how much work is done by the man in pushing the

mower 7.4m?

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Answers (1)
  1. 5 January, 19:34
    0
    The force is 186.5 N. 3.8% of the force is directed downward. So the vertical component of the force is:

    Fᵧ = 0.038 (186.5 N)

    Fᵧ = 7.087 N

    The horizontal component is found with Pythagorean theorem:

    F² = Fₓ² + Fᵧ²

    (186.5 N) ² = Fₓ² + (7.087 N) ²

    Fₓ = 186.4 N

    So the work done is:

    W = Fd

    W = (186.4 N) (7.4 m)

    W = 1379 J

    Round as needed.
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