In a diffraction experiment, light of 600nm wavelengthproduces

a first-order maximum 0.350 mm from the central maximum ona distant

screen. A second monochromatic source produces athird-order maximum

0.870mm from the central maximum when it passesthrough the same

diffraction grating. What is the wavelengthof the light from the

second source?

Question

28 April, 14:55

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Answers (1)

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Eve Marks · Answer 1

497 nanometers is the answer.

λ^2 = (y^2/, m^2) d/R = (y^2/m^2) (m^1/y^1) λ^1 = (0.870mm/3) (1/0.350mm) 600nm=497nm