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27 December, 17:42

A light spring has a force constant of 70 N/m and is used to pull a 10 kg box on a horizontal frictionless surface. If the box has an acceleration of 5

m/s2, by how much does the spring stretch if it pulls on the sled at 30.0° above the horizontal?

88.9 cm

50.7 cm

82.4 cm

66.3 cm

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Answers (1)
  1. 27 December, 18:11
    0
    82.4 cm

    Explanation:

    ∑F = ma

    kx cos θ = ma

    x = ma / (k cos θ)

    x = (10 kg) (5 m/s²) / (70 N/m cos 30.0°)

    x = 0.824 m

    x = 82.4 cm
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