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6 November, 03:57

How many moles of nitrogen atoms are there present in 28 grams of Nitrogen gas

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  1. 6 November, 04:09
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    Answer:2 * 6.022 * 10²³ atoms.

    Explanation:It's 1 mole = mass of the nitrogen

    Here we can say, mass of the nitrogen=1mole

    1mole=6.022*10^23

    And we can get the mass of nitrogen by

    Mass of nitrogen=no. Of protons+neutrons

    Mass of nitrogen=7+7

    Mass of nitrogen=14u

    So we get that,

    Mass of the nitrogen=1mole

    Then,

    14g=1mole

    28g=xmole

    14:28::1:x

    14x=28

    X=2

    So,

    28g=2moles
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