Ask Question
3 September, 03:25

Glucose, labeled with 14C in different carbon atoms, is added to a crude extract of a tissue rich in enzymes of the pentose phosphate pathway. The most rapid production of 14CO2 will occur when the glucose is labeled in:

a. C-1

b. C-3

c. C-4

d. C-5

e. C-6

+3
Answers (1)
  1. 3 September, 03:53
    0
    A. C-1

    Explanation:

    During the pentose phosphate pathway, glucose 6-phosphate is first converted into 6-phosphoglucono-lactone in the reaction catalyzed by glucose 6-phosphate dehydrogenase. The 6-phosphoglucono-lactone is then converted into 6-phospho-gluconate which in turn undergoes decarboxylation to form D-ribulose 5-phosphate and the C-1 of original glucose 6-phosphate is released in form of CO2.

    Therefore, to observe the most rapid production of labeled carbon atom in form of CO2, the C-1 of glucose should be labeled.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Glucose, labeled with 14C in different carbon atoms, is added to a crude extract of a tissue rich in enzymes of the pentose phosphate ...” in 📗 Biology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers