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11 December, 15:52

The pharmacist needs to measure out 35 grams of a 70% powder using the 50% and 90% powders he has in stock. how much of each powder is required?

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  1. 11 December, 15:57
    0
    let us say that:

    x = mass of 50% powder

    y = mass of 90% powder

    eqtn 1 overall mass balance: x + y = 35

    eqtn 2 poweder balance: 0.50 x + 0.90 y = 0.70 * 35 = > 0.50 x + 0.90 y = 24.5

    Combining equations 1 and 2:

    0.50 (35 - y) + 0.90 y = 24.5

    17.5 - 0.50 y + 0.90 y = 24.5

    0.40 y = 7

    y = 17.5 grams

    x = 35 - y = 35 - 17.5 = 17.5 grams

    So equal amounts of 17.5 grams each are needed.
  2. 11 December, 16:11
    0
    The pharmacist needs to measure out 17.5 grams of the 50% powder and 17.5 grams of the 90% powder and should end up with 35 grams of the 70% powder thus making for an easy method of calculation for mixing the two powders.
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