Ask Question
22 July, 18:58

A reaction has a forward rate constant of 2.3 * 106 s-1 and an equilibrium constant of 4.0 * 108. what is the rate constant for the reverse reaction?

+3
Answers (1)
  1. 22 July, 19:28
    0
    Answer is: 5,75·10⁻¹.

    Kf = 2,3·10⁶ 1/s.

    K = 4,0·10⁸ 1/s.

    Kr = ?

    Kf - forward rate constant.

    K - equilibrium constant.

    Kr - reverse rate constant.

    Since both Kf and Kr are constants at a given temperature, their ratio is also a constant that is equal to the equilibrium constant K.

    K = Kf/Kr.

    Kr = Kf/K = 2,3·10⁶ 1/s : 4,0·10⁸ 1/s = 5,75·10⁻¹.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A reaction has a forward rate constant of 2.3 * 106 s-1 and an equilibrium constant of 4.0 * 108. what is the rate constant for the reverse ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers