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21 January, 02:48

If the pressure changes from 1 atm to 3 atm, what does the volume of 30 L change to

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  1. 21 January, 02:58
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    Answer: 10L

    Explanation:

    Given that:

    Initial pressure P1 = 1 atm

    New pressure P2 = 3 atm

    Initial volume V2 = 30 L

    New volume V2 = ?

    Since pressure and volume are involved, apply the formula for Boyle's law

    P1V1 = P2V2

    1 atm x 30L = 3 atm x V2

    30 atm L = 3 atm x V2

    V2 = (30 atm L / 3 atm)

    V2 = 10L

    Thus, volume changed to 10 liters
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