A sample of chlorine gas is held at a pressure of 1023.6 Pa. When the pressure is decreased to 811.4 Pa the volume is 25.6 L. What was the original volume?

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Chemistry

12 August, 05:09

A sample of chlorine gas is held at a pressure of 1023.6 Pa. When the pressure is decreased to 811.4 Pa the volume is 25.6 L. What was the original volume?

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Answers (1)

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Joslyn Foley · Answer 1

V1 = 20.3L

Explanation:

P2 = 811.4Pa

V2 = 25.6L

P1 = 1023.6Pa

V1 = ?

To solve this question, we'll have to use Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

Mathematically,

V = k / P, k = PV

P1 * V1 = P2 * V2 = P3 * V3 = ... = Pn * Vn

P1 * V1 = P2 * V2

Solve for V1

V1 = (P2 * V2) / P1

V1 = (811.4 * 25.6) / 1023.6Pa

V1 = 20771.84 / 1023.6

V1 = 20.29 = 20.3L

The initial volume was 20.3L