An element consists of 1.40% of an isotope with mass 203.973 amu, 24.10% of an isotope with mass 205.9745 amu, 22.10% of an isotope with mass 206.9759 amu, and 52.40% of an isotope with mass 207.9766 amu. Calculate the average atomic mass and identify the element.

The answer to your question is: 207.21 amu The element is Lead

Explanation:

Data Percent Molecular mass

1 1.40% 203.973 amu

2 24.1 % 205.9745 amu

3 22.10% 206.9759 amu

4 52.40% 207.9766 amu

Average atomic mass = (0.014 x 203.973) + (0.241 x 205.9745) + (0.2210 X 206. 9759) + (0.524 x 207.9766)

= 2.855 + 49.6399 + 45.7417 + 108.9797

= 207.21 amu The element is Lead