Calculate the temperatureoC that 0.2 moles of gas in a

balloon at 2.0 atmoccupies 2.0 L.

- 29.54 °C

Explanation:

Given that:-

Pressure = 2.0 atm

Volume = 2.0 L

n = 0.2 mol

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L. atm/K. mol

Applying the equation as:

2.0 atm * 2.0 L = 0.2 mol * 0.0821 L. atm/K. mol * T

⇒T = 243.61 K

The conversion of T (K) to T (°C) is shown below:

T (°C) = T (K) - 273.15

So,

T = (243.61 - 273.15) K = - 29.54 °C

- 29.54 °C is the temperature.