What volume would 3.01•1023 molecules of oxygen gas occupy at STP? 11.2 mL 22.4 mL 11.2 L 22.4 L

Question

Stephanie Stone

Chemistry

9 November, 22:58

What volume would 3.01•1023 molecules of oxygen gas occupy at STP? 11.2 mL 22.4 mL 11.2 L 22.4 L

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Lainey Ochoa · Answer 1

One mole of substance contains 6.02 x 10²³ particles and each mole of gas occupies 22.4 Liters at STP.

Moles of oxygen: 3.01 x 10²³ / 6.02 x 10²³ = 0.5

Volume of oxygen: 0.5 x 22.4

Volume of oxygen = 11.2 L