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9 November, 22:58

What volume would 3.01•1023 molecules of oxygen gas occupy at STP? 11.2 mL 22.4 mL 11.2 L 22.4 L

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  1. 9 November, 23:21
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    One mole of substance contains 6.02 x 10²³ particles and each mole of gas occupies 22.4 Liters at STP.

    Moles of oxygen: 3.01 x 10²³ / 6.02 x 10²³ = 0.5

    Volume of oxygen: 0.5 x 22.4

    Volume of oxygen = 11.2 L
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