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9 July, 15:23

If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under the same conditions?2 CO (g) + O2 (g) - --> 2 CO2 (g)

a. 1.5 L

b. 3.0 L

c. 4.5 L

d. 6.0 L,

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Answers (1)
  1. 9 July, 15:38
    0
    The volume of CO2 produced is 6.0 L (option D)

    Explanation:

    Step 1: Data given

    Volume of oxygen = 3.0 L

    Carbon monoxide = CO = in excess

    Step 2: The balanced equation

    2 CO (g) + O2 (g) → 2 CO2 (g)

    Step 3: Calculate moles of O2

    1 mol of gas at STP = 22.4 L

    3.0 L = 0.134 moles

    Step 3: Calculate moles of CO2

    For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

    For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

    Step 4: Calculate volume of CO2

    1 mol = 22.4 L

    0.268 mol = 22.4 * 0.268 = 6.0 L

    The volume of CO2 produced is 6.0 L
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