Sodium metal reacts with chlorine gas to produce sodium chloride. What mass (grams) of sodium metal would be needed to fully react with 2.3 moles of chlorine gas?

105.8 g of Na would be required

Explanation:

Let's think the reaction:

2Na (s) + Cl₂ (g) → 2NaCl (s)

1 mol of chlorine reacts with 2 moles of sodium

Then, 2.3 moles of Cl₂ would react with (2.3.2) / 1 = 4.6 moles

Let's determine the mass of them.

4.6 mol. 23 g/mol = 105.8 g